8*4=x(x*7)-(x*3)

Solution for 8*4=x(x*7)-(x*3) equation:

8*4=x(x*7)-(x*3)

We move all terms to the left:

8*4-(x(x*7)-(x*3))=0

We add all the numbers together, and all the variables

-(x(+x*7)-(+x*3))+8*4=0

We add all the numbers together, and all the variables

-(x(+x*7)-(+x*3))+32=0


We calculate terms in parentheses: -(x(+x*7)-(+x*3)), so:

x(+x*7)-(+x*3)

We multiply parentheses

7x^2-(+x*3)

We get rid of parentheses

7x^2-x*3

Wy multiply elements

7x^2-3x

Back to the equation:

-(7x^2-3x)


We get rid of parentheses

-7x^2+3x+32=0

a = -7; b = 3; c = +32;
Δ = b2-4ac
Δ = 32-4·(-7)·32
Δ = 905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{905}}{2*-7}=\frac{-3-\sqrt{905}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{905}}{2*-7}=\frac{-3+\sqrt{905}}{-14}
$