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-8/5h=3
We move all terms to the left:
-8/5h-(3)=0
Domain of the equation: 5h!=0We multiply all the terms by the denominator
h!=0/5
h!=0
h∈R
-3*5h-8=0
Wy multiply elements
-15h-8=0
We move all terms containing h to the left, all other terms to the right
-15h=8
h=8/-15
h=-8/15
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