8(z+1)-3(z-1)=2(z-3)+2(z-1)

Solution for 8(z+1)-3(z-1)=2(z-3)+2(z-1) equation:

8(z+1)-3(z-1)=2(z-3)+2(z-1)

We move all terms to the left:

8(z+1)-3(z-1)-(2(z-3)+2(z-1))=0

We multiply parentheses

8z-3z-(2(z-3)+2(z-1))+8+3=0


We calculate terms in parentheses: -(2(z-3)+2(z-1)), so:

2(z-3)+2(z-1)

We multiply parentheses

2z+2z-6-2

We add all the numbers together, and all the variables

4z-8

Back to the equation:

-(4z-8)


We add all the numbers together, and all the variables

5z-(4z-8)+11=0

We get rid of parentheses

5z-4z+8+11=0

We add all the numbers together, and all the variables

z+19=0

We move all terms containing z to the left, all other terms to the right

z=-19