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5(3y-9)-7=5(y-2)+28
We move all terms to the left:
5(3y-9)-7-(5(y-2)+28)=0
We multiply parentheses
15y-(5(y-2)+28)-45-7=0
We calculate terms in parentheses: -(5(y-2)+28), so:We add all the numbers together, and all the variables
5(y-2)+28
We multiply parentheses
5y-10+28
We add all the numbers together, and all the variables
5y+18
Back to the equation:
-(5y+18)
15y-(5y+18)-52=0
We get rid of parentheses
15y-5y-18-52=0
We add all the numbers together, and all the variables
10y-70=0
We move all terms containing y to the left, all other terms to the right
10y=70
y=70/10
y=7
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