8(y-6)=-12(y-1)

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Solution for 8(y-6)=-12(y-1) equation: 



8(y-6)=-12(y-1)

We move all terms to the left:

8(y-6)-(-12(y-1))=0

We multiply parentheses

8y-(-12(y-1))-48=0



We calculate terms in parentheses: -(-12(y-1)), so:

-12(y-1)

We multiply parentheses

-12y+12

Back to the equation:

-(-12y+12)



We get rid of parentheses

8y+12y-12-48=0

We add all the numbers together, and all the variables

20y-60=0

We move all terms containing y to the left, all other terms to the right

20y=60

y=60/20

y=3

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