6(b+3)=3b+30

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Solution for 6(b+3)=3b+30 equation: 



6(b+3)=3b+30

We move all terms to the left:

6(b+3)-(3b+30)=0

We multiply parentheses

6b-(3b+30)+18=0

We get rid of parentheses

6b-3b-30+18=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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