8(y-3)=6y-28

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Solution for 8(y-3)=6y-28 equation: 



8(y-3)=6y-28

We move all terms to the left:

8(y-3)-(6y-28)=0

We multiply parentheses

8y-(6y-28)-24=0

We get rid of parentheses

8y-6y+28-24=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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