2(t-5)-3(3t-2)=9-5(5t+4)

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Solution for 2(t-5)-3(3t-2)=9-5(5t+4) equation:



2(t-5)-3(3t-2)=9-5(5t+4)
We move all terms to the left:
2(t-5)-3(3t-2)-(9-5(5t+4))=0
We multiply parentheses
2t-9t-(9-5(5t+4))-10+6=0
We calculate terms in parentheses: -(9-5(5t+4)), so:
9-5(5t+4)
determiningTheFunctionDomain -5(5t+4)+9
We multiply parentheses
-25t-20+9
We add all the numbers together, and all the variables
-25t-11
Back to the equation:
-(-25t-11)
We add all the numbers together, and all the variables
-7t-(-25t-11)-4=0
We get rid of parentheses
-7t+25t+11-4=0
We add all the numbers together, and all the variables
18t+7=0
We move all terms containing t to the left, all other terms to the right
18t=-7
t=-7/18
t=-7/18

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