8(y-3)=10-2y

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Solution for 8(y-3)=10-2y equation: 



8(y-3)=10-2y

We move all terms to the left:

8(y-3)-(10-2y)=0

We add all the numbers together, and all the variables

8(y-3)-(-2y+10)=0

We multiply parentheses

8y-(-2y+10)-24=0

We get rid of parentheses

8y+2y-10-24=0

We add all the numbers together, and all the variables

10y-34=0

We move all terms containing y to the left, all other terms to the right

10y=34

y=34/10

y=3+2/5

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