2(x+3)-4(3-2x)=100-4(5x+20)

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Solution for 2(x+3)-4(3-2x)=100-4(5x+20) equation: 



2(x+3)-4(3-2x)=100-4(5x+20)

We move all terms to the left:

2(x+3)-4(3-2x)-(100-4(5x+20))=0

We add all the numbers together, and all the variables

2(x+3)-4(-2x+3)-(100-4(5x+20))=0

We multiply parentheses

2x+8x-(100-4(5x+20))+6-12=0



We calculate terms in parentheses: -(100-4(5x+20)), so:

100-4(5x+20)

determiningTheFunctionDomain
-4(5x+20)+100

We multiply parentheses

-20x-80+100

We add all the numbers together, and all the variables

-20x+20

Back to the equation:

-(-20x+20)



We add all the numbers together, and all the variables

10x-(-20x+20)-6=0

We get rid of parentheses

10x+20x-20-6=0

We add all the numbers together, and all the variables

30x-26=0

We move all terms containing x to the left, all other terms to the right

30x=26

x=26/30

x=13/15

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