8(y-1)-2(2+y)=3(y+4)-(5-y)

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Solution for 8(y-1)-2(2+y)=3(y+4)-(5-y) equation: 



8(y-1)-2(2+y)=3(y+4)-(5-y)

We move all terms to the left:

8(y-1)-2(2+y)-(3(y+4)-(5-y))=0

We add all the numbers together, and all the variables

8(y-1)-2(y+2)-(3(y+4)-(-1y+5))=0

We multiply parentheses

8y-2y-(3(y+4)-(-1y+5))-8-4=0



We calculate terms in parentheses: -(3(y+4)-(-1y+5)), so:

3(y+4)-(-1y+5)

We multiply parentheses

3y-(-1y+5)+12

We get rid of parentheses

3y+1y-5+12

We add all the numbers together, and all the variables

4y+7

Back to the equation:

-(4y+7)



We add all the numbers together, and all the variables

6y-(4y+7)-12=0

We get rid of parentheses

6y-4y-7-12=0

We add all the numbers together, and all the variables

2y-19=0

We move all terms containing y to the left, all other terms to the right

2y=19

y=19/2

y=9+1/2

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