6(x+1)-2(5-2x)=4x-(x+4)+7

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Solution for 6(x+1)-2(5-2x)=4x-(x+4)+7 equation: 



6(x+1)-2(5-2x)=4x-(x+4)+7

We move all terms to the left:

6(x+1)-2(5-2x)-(4x-(x+4)+7)=0

We add all the numbers together, and all the variables

6(x+1)-2(-2x+5)-(4x-(x+4)+7)=0

We multiply parentheses

6x+4x-(4x-(x+4)+7)+6-10=0



We calculate terms in parentheses: -(4x-(x+4)+7), so:

4x-(x+4)+7

We get rid of parentheses

4x-x-4+7

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

10x-(3x+3)-4=0

We get rid of parentheses

10x-3x-3-4=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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