8(y+4)=(y-1)=70-3y

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Solution for 8(y+4)=(y-1)=70-3y equation: 



8(y+4)=(y-1)=70-3y

We move all terms to the left:

8(y+4)-((y-1))=0

We multiply parentheses

8y-((y-1))+32=0



We calculate terms in parentheses: -((y-1)), so:

(y-1)

We get rid of parentheses

y-1

Back to the equation:

-(y-1)



We get rid of parentheses

8y-y+1+32=0

We add all the numbers together, and all the variables

7y+33=0

We move all terms containing y to the left, all other terms to the right

7y=-33

y=-33/7

y=-4+5/7

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