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6-2x=x-4(2+x)
We move all terms to the left:
6-2x-(x-4(2+x))=0
We add all the numbers together, and all the variables
-2x-(x-4(x+2))+6=0
We calculate terms in parentheses: -(x-4(x+2)), so:We get rid of parentheses
x-4(x+2)
We multiply parentheses
x-4x-8
We add all the numbers together, and all the variables
-3x-8
Back to the equation:
-(-3x-8)
-2x+3x+8+6=0
We add all the numbers together, and all the variables
x+14=0
We move all terms containing x to the left, all other terms to the right
x=-14
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