8(y+4)-2y(y-1)=70+-3y

Solution for 8(y+4)-2y(y-1)=70+-3y equation:

8(y+4)-2y(y-1)=70+-3y

We move all terms to the left:

8(y+4)-2y(y-1)-(70+-3y)=0

We add all the numbers together, and all the variables

8(y+4)-2y(y-1)-(-3y)=0

We multiply parentheses

-2y^2+8y+2y-(-3y)+32=0

We get rid of parentheses

-2y^2+8y+2y+3y+32=0

We add all the numbers together, and all the variables

-2y^2+13y+32=0

a = -2; b = 13; c = +32;
Δ = b2-4ac
Δ = 132-4·(-2)·32
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5\sqrt{17}}{2*-2}=\frac{-13-5\sqrt{17}}{-4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5\sqrt{17}}{2*-2}=\frac{-13+5\sqrt{17}}{-4}
$