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(4m-7)(m-7)=0
We multiply parentheses ..
(+4m^2-28m-7m+49)=0
We get rid of parentheses
4m^2-28m-7m+49=0
We add all the numbers together, and all the variables
4m^2-35m+49=0
a = 4; b = -35; c = +49;
Δ = b2-4ac
Δ = -352-4·4·49
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-21}{2*4}=\frac{14}{8} =1+3/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+21}{2*4}=\frac{56}{8} =7 $
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