8(y+1)-3y=6(2y-6)

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Solution for 8(y+1)-3y=6(2y-6) equation: 



8(y+1)-3y=6(2y-6)

We move all terms to the left:

8(y+1)-3y-(6(2y-6))=0

We add all the numbers together, and all the variables

-3y+8(y+1)-(6(2y-6))=0

We multiply parentheses

-3y+8y-(6(2y-6))+8=0



We calculate terms in parentheses: -(6(2y-6)), so:

6(2y-6)

We multiply parentheses

12y-36

Back to the equation:

-(12y-36)



We add all the numbers together, and all the variables

5y-(12y-36)+8=0

We get rid of parentheses

5y-12y+36+8=0

We add all the numbers together, and all the variables

-7y+44=0

We move all terms containing y to the left, all other terms to the right

-7y=-44

y=-44/-7

y=6+2/7

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