8(x-4)=6x-40

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Solution for 8(x-4)=6x-40 equation: 



8(x-4)=6x-40

We move all terms to the left:

8(x-4)-(6x-40)=0

We multiply parentheses

8x-(6x-40)-32=0

We get rid of parentheses

8x-6x+40-32=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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