(20-2x)16+10x=0

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Solution for (20-2x)16+10x=0 equation: 



(20-2x)16+10x=0

We add all the numbers together, and all the variables

(-2x+20)16+10x=0

We add all the numbers together, and all the variables

10x+(-2x+20)16=0

We multiply parentheses

10x-32x+320=0

We add all the numbers together, and all the variables

-22x+320=0

We move all terms containing x to the left, all other terms to the right

-22x=-320

x=-320/-22

x=14+6/11

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