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6x+1=-(3x/5)+5
We move all terms to the left:
6x+1-(-(3x/5)+5)=0
We add all the numbers together, and all the variables
6x-(-(+3x/5)+5)+1=0
We multiply all the terms by the denominator
6x*5)+5)-(-(+3x+1*5)+5)=0
We add all the numbers together, and all the variables
6x*5)+5)-(-(3x+5)+5)=0
We add all the numbers together, and all the variables
6x*5)+5)-(-(3x=0
Wy multiply elements
30x^2=0
a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{60}=0$
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