8(x-4)-(2x-1)=12

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Solution for 8(x-4)-(2x-1)=12 equation: 



8(x-4)-(2x-1)=12

We move all terms to the left:

8(x-4)-(2x-1)-(12)=0

We multiply parentheses

8x-(2x-1)-32-12=0

We get rid of parentheses

8x-2x+1-32-12=0

We add all the numbers together, and all the variables

6x-43=0

We move all terms containing x to the left, all other terms to the right

6x=43

x=43/6

x=7+1/6

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