2(5-f)=20

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Solution for 2(5-f)=20 equation: 



2(5-f)=20

We move all terms to the left:

2(5-f)-(20)=0

We add all the numbers together, and all the variables

2(-1f+5)-20=0

We multiply parentheses

-2f+10-20=0

We add all the numbers together, and all the variables

-2f-10=0

We move all terms containing f to the left, all other terms to the right

-2f=10

f=10/-2

f=-5

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