8(x-3)=(16(x+1)/2

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Solution for 8(x-3)=(16(x+1)/2 equation: 



8(x-3)=(16(x+1)/2

We move all terms to the left:

8(x-3)-((16(x+1)/2)=0

We multiply parentheses

8x-((16(x+1)/2)-24=0

We multiply all the terms by the denominator


8x*2)-24-((16(x+1)=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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