3(3+k)=2(2+k)

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Solution for 3(3+k)=2(2+k) equation: 



3(3+k)=2(2+k)

We move all terms to the left:

3(3+k)-(2(2+k))=0

We add all the numbers together, and all the variables

3(k+3)-(2(k+2))=0

We multiply parentheses

3k-(2(k+2))+9=0



We calculate terms in parentheses: -(2(k+2)), so:

2(k+2)

We multiply parentheses

2k+4

Back to the equation:

-(2k+4)



We get rid of parentheses

3k-2k-4+9=0

We add all the numbers together, and all the variables

k+5=0

We move all terms containing k to the left, all other terms to the right

k=-5

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