8(x-3)-6(x-2)=2(x+2)-8(5-x)

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Solution for 8(x-3)-6(x-2)=2(x+2)-8(5-x) equation: 



8(x-3)-6(x-2)=2(x+2)-8(5-x)

We move all terms to the left:

8(x-3)-6(x-2)-(2(x+2)-8(5-x))=0

We add all the numbers together, and all the variables

8(x-3)-6(x-2)-(2(x+2)-8(-1x+5))=0

We multiply parentheses

8x-6x-(2(x+2)-8(-1x+5))-24+12=0



We calculate terms in parentheses: -(2(x+2)-8(-1x+5)), so:

2(x+2)-8(-1x+5)

We multiply parentheses

2x+8x+4-40

We add all the numbers together, and all the variables

10x-36

Back to the equation:

-(10x-36)



We add all the numbers together, and all the variables

2x-(10x-36)-12=0

We get rid of parentheses

2x-10x+36-12=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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