40-5(8-4y)=6y

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Solution for 40-5(8-4y)=6y equation: 



40-5(8-4y)=6y

We move all terms to the left:

40-5(8-4y)-(6y)=0

We add all the numbers together, and all the variables

-5(-4y+8)-6y+40=0

We add all the numbers together, and all the variables

-6y-5(-4y+8)+40=0

We multiply parentheses

-6y+20y-40+40=0

We add all the numbers together, and all the variables

14y=0

y=0/14

y=0

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