8(x-3)-(6-3x)=2(x+2)-5(5-x)

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Solution for 8(x-3)-(6-3x)=2(x+2)-5(5-x) equation: 



8(x-3)-(6-3x)=2(x+2)-5(5-x)

We move all terms to the left:

8(x-3)-(6-3x)-(2(x+2)-5(5-x))=0

We add all the numbers together, and all the variables

8(x-3)-(-3x+6)-(2(x+2)-5(-1x+5))=0

We multiply parentheses

8x-(-3x+6)-(2(x+2)-5(-1x+5))-24=0

We get rid of parentheses

8x+3x-(2(x+2)-5(-1x+5))-6-24=0



We calculate terms in parentheses: -(2(x+2)-5(-1x+5)), so:

2(x+2)-5(-1x+5)

We multiply parentheses

2x+5x+4-25

We add all the numbers together, and all the variables

7x-21

Back to the equation:

-(7x-21)



We add all the numbers together, and all the variables

11x-(7x-21)-30=0

We get rid of parentheses

11x-7x+21-30=0

We add all the numbers together, and all the variables

4x-9=0

We move all terms containing x to the left, all other terms to the right

4x=9

x=9/4

x=2+1/4

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