3(-2t+1)=4-(2t+1)

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Solution for 3(-2t+1)=4-(2t+1) equation: 



3(-2t+1)=4-(2t+1)

We move all terms to the left:

3(-2t+1)-(4-(2t+1))=0

We multiply parentheses

-6t-(4-(2t+1))+3=0



We calculate terms in parentheses: -(4-(2t+1)), so:

4-(2t+1)

determiningTheFunctionDomain
-(2t+1)+4

We get rid of parentheses

-2t-1+4

We add all the numbers together, and all the variables

-2t+3

Back to the equation:

-(-2t+3)



We get rid of parentheses

-6t+2t-3+3=0

We add all the numbers together, and all the variables

-4t=0

t=0/-4

t=0

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