8(x-2)-3(1-x)=9(x+2)=1

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Solution for 8(x-2)-3(1-x)=9(x+2)=1 equation: 



8(x-2)-3(1-x)=9(x+2)=1

We move all terms to the left:

8(x-2)-3(1-x)-(9(x+2))=0

We add all the numbers together, and all the variables

8(x-2)-3(-1x+1)-(9(x+2))=0

We multiply parentheses

8x+3x-(9(x+2))-16-3=0



We calculate terms in parentheses: -(9(x+2)), so:

9(x+2)

We multiply parentheses

9x+18

Back to the equation:

-(9x+18)



We add all the numbers together, and all the variables

11x-(9x+18)-19=0

We get rid of parentheses

11x-9x-18-19=0

We add all the numbers together, and all the variables

2x-37=0

We move all terms containing x to the left, all other terms to the right

2x=37

x=37/2

x=18+1/2

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