8(x-2)+2x=10(x+2)-36

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Solution for 8(x-2)+2x=10(x+2)-36 equation: 



8(x-2)+2x=10(x+2)-36

We move all terms to the left:

8(x-2)+2x-(10(x+2)-36)=0

We add all the numbers together, and all the variables

2x+8(x-2)-(10(x+2)-36)=0

We multiply parentheses

2x+8x-(10(x+2)-36)-16=0



We calculate terms in parentheses: -(10(x+2)-36), so:

10(x+2)-36

We multiply parentheses

10x+20-36

We add all the numbers together, and all the variables

10x-16

Back to the equation:

-(10x-16)



We add all the numbers together, and all the variables

10x-(10x-16)-16=0

We get rid of parentheses

10x-10x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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