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2/3x(x-9)+2=x-6
We move all terms to the left:
2/3x(x-9)+2-(x-6)=0
Domain of the equation: 3x(x-9)!=0We get rid of parentheses
x∈R
2/3x(x-9)-x+6+2=0
We multiply all the terms by the denominator
-x*3x(x-9)+6*3x(x-9)+2*3x(x-9)+2=0
Wy multiply elements
-3x^2(x+18x(x+6x(x+2=0
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