8(x-12)=4(x+8)

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Solution for 8(x-12)=4(x+8) equation: 



8(x-12)=4(x+8)

We move all terms to the left:

8(x-12)-(4(x+8))=0

We multiply parentheses

8x-(4(x+8))-96=0



We calculate terms in parentheses: -(4(x+8)), so:

4(x+8)

We multiply parentheses

4x+32

Back to the equation:

-(4x+32)



We get rid of parentheses

8x-4x-32-96=0

We add all the numbers together, and all the variables

4x-128=0

We move all terms containing x to the left, all other terms to the right

4x=128

x=128/4

x=32

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