8(x-1)-7=2(x+2)+5

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Solution for 8(x-1)-7=2(x+2)+5 equation: 



8(x-1)-7=2(x+2)+5

We move all terms to the left:

8(x-1)-7-(2(x+2)+5)=0

We multiply parentheses

8x-(2(x+2)+5)-8-7=0



We calculate terms in parentheses: -(2(x+2)+5), so:

2(x+2)+5

We multiply parentheses

2x+4+5

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

8x-(2x+9)-15=0

We get rid of parentheses

8x-2x-9-15=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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