13(z+3)-3(z-3)=6(z-1)+3(z-1)

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Solution for 13(z+3)-3(z-3)=6(z-1)+3(z-1) equation: 



13(z+3)-3(z-3)=6(z-1)+3(z-1)

We move all terms to the left:

13(z+3)-3(z-3)-(6(z-1)+3(z-1))=0

We multiply parentheses

13z-3z-(6(z-1)+3(z-1))+39+9=0



We calculate terms in parentheses: -(6(z-1)+3(z-1)), so:

6(z-1)+3(z-1)

We multiply parentheses

6z+3z-6-3

We add all the numbers together, and all the variables

9z-9

Back to the equation:

-(9z-9)



We add all the numbers together, and all the variables

10z-(9z-9)+48=0

We get rid of parentheses

10z-9z+9+48=0

We add all the numbers together, and all the variables

z+57=0

We move all terms containing z to the left, all other terms to the right

z=-57

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