8(x+2)=4(x+1)

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Solution for 8(x+2)=4(x+1) equation: 



8(x+2)=4(x+1)

We move all terms to the left:

8(x+2)-(4(x+1))=0

We multiply parentheses

8x-(4(x+1))+16=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

8x-4x-4+16=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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