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3/5(x+1)=1/20(x+6)
We move all terms to the left:
3/5(x+1)-(1/20(x+6))=0
Domain of the equation: 5(x+1)!=0
x∈R
Domain of the equation: 20(x+6))!=0We calculate fractions
x∈R
(60xx/(5(x+1)*20(x+6)))+(-5xx/(5(x+1)*20(x+6)))=0
We calculate terms in parentheses: +(60xx/(5(x+1)*20(x+6))), so:
60xx/(5(x+1)*20(x+6))
We multiply all the terms by the denominator
60xx
Back to the equation:
+(60xx)
We calculate terms in parentheses: +(-5xx/(5(x+1)*20(x+6))), so:We get rid of parentheses
-5xx/(5(x+1)*20(x+6))
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
60xx-5xx=0
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