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8(x+2)-6=2x+6(1+x)
We move all terms to the left:
8(x+2)-6-(2x+6(1+x))=0
We add all the numbers together, and all the variables
8(x+2)-(2x+6(x+1))-6=0
We multiply parentheses
8x-(2x+6(x+1))+16-6=0
We calculate terms in parentheses: -(2x+6(x+1)), so:We add all the numbers together, and all the variables
2x+6(x+1)
We multiply parentheses
2x+6x+6
We add all the numbers together, and all the variables
8x+6
Back to the equation:
-(8x+6)
8x-(8x+6)+10=0
We get rid of parentheses
8x-8x-6+10=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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