8(x+2)+4x+3=5x+4+5(x+1)

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Solution for 8(x+2)+4x+3=5x+4+5(x+1) equation: 



8(x+2)+4x+3=5x+4+5(x+1)

We move all terms to the left:

8(x+2)+4x+3-(5x+4+5(x+1))=0

We add all the numbers together, and all the variables

4x+8(x+2)-(5x+4+5(x+1))+3=0

We multiply parentheses

4x+8x-(5x+4+5(x+1))+16+3=0



We calculate terms in parentheses: -(5x+4+5(x+1)), so:

5x+4+5(x+1)

determiningTheFunctionDomain
5x+5(x+1)+4

We multiply parentheses

5x+5x+5+4

We add all the numbers together, and all the variables

10x+9

Back to the equation:

-(10x+9)



We add all the numbers together, and all the variables

12x-(10x+9)+19=0

We get rid of parentheses

12x-10x-9+19=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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