8(x+2)+3(2x-1)=27

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Solution for 8(x+2)+3(2x-1)=27 equation: 



8(x+2)+3(2x-1)=27

We move all terms to the left:

8(x+2)+3(2x-1)-(27)=0

We multiply parentheses

8x+6x+16-3-27=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

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