8(x+2)+3(2x-1)=27*

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Solution for 8(x+2)+3(2x-1)=27* equation: 



8(x+2)+3(2x-1)=27*

We move all terms to the left:

8(x+2)+3(2x-1)-(27*)=0

We add all the numbers together, and all the variables

8(x+2)+3(2x-1)-0=0

We add all the numbers together, and all the variables

8(x+2)+3(2x-1)=0

We multiply parentheses

8x+6x+16-3=0

We add all the numbers together, and all the variables

14x+13=0

We move all terms containing x to the left, all other terms to the right

14x=-13

x=-13/14

x=-13/14

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