8(x+1)+1=4x+4(2+x)

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Solution for 8(x+1)+1=4x+4(2+x) equation: 



8(x+1)+1=4x+4(2+x)

We move all terms to the left:

8(x+1)+1-(4x+4(2+x))=0

We add all the numbers together, and all the variables

8(x+1)-(4x+4(x+2))+1=0

We multiply parentheses

8x-(4x+4(x+2))+8+1=0



We calculate terms in parentheses: -(4x+4(x+2)), so:

4x+4(x+2)

We multiply parentheses

4x+4x+8

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

8x-(8x+8)+9=0

We get rid of parentheses

8x-8x-8+9=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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