5(6+c)=4(2+c)

Solution for 5(6+c)=4(2+c) equation:

5(6+c)=4(2+c)

We move all terms to the left:

5(6+c)-(4(2+c))=0

We add all the numbers together, and all the variables

5(c+6)-(4(c+2))=0

We multiply parentheses

5c-(4(c+2))+30=0


We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)


We get rid of parentheses

5c-4c-8+30=0

We add all the numbers together, and all the variables

c+22=0

We move all terms containing c to the left, all other terms to the right

c=-22