8(x+1)(x-1)=0

Solution for 8(x+1)(x-1)=0 equation:

Simplifying
8(x + 1)(x + -1) = 0

Reorder the terms:
8(1 + x)(x + -1) = 0

Reorder the terms:
8(1 + x)(-1 + x) = 0

Multiply (1 + x) * (-1 + x)
8(1(-1 + x) + x(-1 + x)) = 0
8((-1 * 1 + x * 1) + x(-1 + x)) = 0
8((-1 + 1x) + x(-1 + x)) = 0
8(-1 + 1x + (-1 * x + x * x)) = 0
8(-1 + 1x + (-1x + x2)) = 0

Combine like terms: 1x + -1x = 0
8(-1 + 0 + x2) = 0
8(-1 + x2) = 0
(-1 * 8 + x2 * 8) = 0
(-8 + 8x2) = 0

Solving
-8 + 8x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 8x2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 8x2 = 0 + 8
8x2 = 0 + 8

Combine like terms: 0 + 8 = 8
8x2 = 8

Divide each side by '8'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}