(8x+1)(8x-1)=0

Solution for (8x+1)(8x-1)=0 equation:

Simplifying
(8x + 1)(8x + -1) = 0

Reorder the terms:
(1 + 8x)(8x + -1) = 0

Reorder the terms:
(1 + 8x)(-1 + 8x) = 0

Multiply (1 + 8x) * (-1 + 8x)
(1(-1 + 8x) + 8x * (-1 + 8x)) = 0
((-1 * 1 + 8x * 1) + 8x * (-1 + 8x)) = 0
((-1 + 8x) + 8x * (-1 + 8x)) = 0
(-1 + 8x + (-1 * 8x + 8x * 8x)) = 0
(-1 + 8x + (-8x + 64x2)) = 0

Combine like terms: 8x + -8x = 0
(-1 + 0 + 64x2) = 0
(-1 + 64x2) = 0

Solving
-1 + 64x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 64x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 64x2 = 0 + 1
64x2 = 0 + 1

Combine like terms: 0 + 1 = 1
64x2 = 1

Divide each side by '64'.
x2 = 0.015625

Simplifying
x2 = 0.015625

Take the square root of each side:
x = {-0.125, 0.125}