8(x)*4(x)=57

Solution for 8(x)*4(x)=57 equation:

8(x)*4(x)=57

We move all terms to the left:

8(x)*4(x)-(57)=0

Wy multiply elements

32x^2-57=0

a = 32; b = 0; c = -57;
Δ = b2-4ac
Δ = 02-4·32·(-57)
Δ = 7296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7296}=\sqrt{64*114}=\sqrt{64}*\sqrt{114}=8\sqrt{114}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{114}}{2*32}=\frac{0-8\sqrt{114}}{64}
=-\frac{8\sqrt{114}}{64}
=-\frac{\sqrt{114}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{114}}{2*32}=\frac{0+8\sqrt{114}}{64}
=\frac{8\sqrt{114}}{64}
=\frac{\sqrt{114}}{8}
$