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3(x+1)+1=2(-2)+x
We move all terms to the left:
3(x+1)+1-(2(-2)+x)=0
We multiply parentheses
3x-(2(-2)+x)+3+1=0
We calculate terms in parentheses: -(2(-2)+x), so:We add all the numbers together, and all the variables
2(-2)+x
determiningTheFunctionDomain x+2(-2)
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
3x-(x-4)+4=0
We get rid of parentheses
3x-x+4+4=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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