8(v-5)=2(v+1)

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Solution for 8(v-5)=2(v+1) equation: 



8(v-5)=2(v+1)

We move all terms to the left:

8(v-5)-(2(v+1))=0

We multiply parentheses

8v-(2(v+1))-40=0



We calculate terms in parentheses: -(2(v+1)), so:

2(v+1)

We multiply parentheses

2v+2

Back to the equation:

-(2v+2)



We get rid of parentheses

8v-2v-2-40=0

We add all the numbers together, and all the variables

6v-42=0

We move all terms containing v to the left, all other terms to the right

6v=42

v=42/6

v=7

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