5(4+2b)=100

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Solution for 5(4+2b)=100 equation: 



5(4+2b)=100

We move all terms to the left:

5(4+2b)-(100)=0

We add all the numbers together, and all the variables

5(2b+4)-100=0

We multiply parentheses

10b+20-100=0

We add all the numbers together, and all the variables

10b-80=0

We move all terms containing b to the left, all other terms to the right

10b=80

b=80/10

b=8

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