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8(v+4)-2v=2(3v+1)-4
We move all terms to the left:
8(v+4)-2v-(2(3v+1)-4)=0
We add all the numbers together, and all the variables
-2v+8(v+4)-(2(3v+1)-4)=0
We multiply parentheses
-2v+8v-(2(3v+1)-4)+32=0
We calculate terms in parentheses: -(2(3v+1)-4), so:We add all the numbers together, and all the variables
2(3v+1)-4
We multiply parentheses
6v+2-4
We add all the numbers together, and all the variables
6v-2
Back to the equation:
-(6v-2)
6v-(6v-2)+32=0
We get rid of parentheses
6v-6v+2+32=0
We add all the numbers together, and all the variables
34!=0
There is no solution for this equation
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