(5/6)c+(3/4)=(11/12)

Solution for (5/6)c+(3/4)=(11/12) equation:

(5/6)c+(3/4)=(11/12)

We move all terms to the left:

(5/6)c+(3/4)-((11/12))=0


Domain of the equation: 6)c!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

(+5/6)c+(+3/4)-((+11/12))=0

We multiply parentheses

5c^2+(+3/4)-((+11/12))=0

We get rid of parentheses

5c^2+3/4-((+11/12))=0

We calculate fractions


5c^2+()/()+()/()=0

We add all the numbers together, and all the variables

5c^2+2=0

a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation